How to create clone copy session?

symclone -g TestDg create DEV001 sym ld DEV002
Create a clone copy session between the devices DEV001(source) and DEV002(target) in regular diskgroup TestDg. By default this will create a differentail session.That means, we can do a incremental recreate or restore later.This command will make the target device in Not Ready(NR).
Related Questions

  • symdg create mydg -type rdf1
    Create device group mydg of rdf1 type .

  • symrdf -sid 1234 -rdfg 3 -type rdf1 -file rdf.txt -g mydg createpair -establish
    Establish the SRDF relation between the devices given in the file rdf.txt from array 1234(R1) and remote box according to the rdf group .This command start sync between R1 and R2 and also add these devices after creating the device group mydg

  • symaccess -sid 1234 -type initiator -name Host1 create -wwn 1000000000000001
    Creates and initiator group called Host1 by adding the specified wwn

  • symaccess -sid 1234 -type port -name 3E0_4E0_13E0_14E0 -dirport 3e:0,4e:0,13e:0,14e:0 create
    Create the portgroup E0_4E0_13E0_14E0 with specified ports

  • symaccess -sid 1234 -type storage -name Host1 create devs AAA:AAB
    Create the storage group Host1 with specified range of devices

« Back to full question list